dev.to staff

Posted on Apr 10, 2020

Daily Challenge #223 - Responsible Drinking

#challenge

Welcome to the bar!

We recommend you drink 1 glass of water per drink so you're not hungover tomorrow morning. Your fellow coders have bought you several drinks tonight in the form of strings. Return a string suggesting how many glasses of water you should drink to not be hungover.

If you would like to keep things simple, you can consider any "numbered thing" in the string to be a drink. Even "1 bear" => "1 glass of water" or "1 chainsaw and 2 pools" => "3 glasses of water".

Example Pairs
Input 0:
"1 beer"
Output 0:
"1 glass of water"

Input 1:
"1 shot, 5 beers, 2 shots, 1 glass of wine, 1 beer"
Output 1:
"10 glasses of water"

Tests
hydrate("1 beer")
hydrate("2 glasses of wine and 1 shot")
hydrate("1 shot, 5 beers, 2 shots, 1 glass of wine, 1 beer")

Good luck!

This challenge comes from taylormb on CodeWars. Thank you to CodeWars, who has licensed redistribution of this challenge under the 2-Clause BSD License!

Want to propose a challenge idea for a future post? Email yo+challenge@dev.to with your suggestions!

Top comments (18)

Vidit Sarkar • Apr 10 '20

Python solution

import re

def hydrate(drinks: str) -> str:
    drinkCount = sum(map(int, re.findall("\d+", drinks))) # total number of drinks
    # this will also work, drinkCount = sum([int(num) for num in drinks.split(" ") if num.isdigit()])

    return str(drinkCount) + " glass" + ("es" if drinkCount > 1 else "") + " of water"


print(hydrate("1 beer")) # output -> 1 glass of water
print(hydrate("2 glasses of wine and 1 shot")) # output -> 3 glasses of water
print(hydrate("1 shot, 5 beers, 2 shots, 1 glass of wine, 1 beer")) # output -> 10 glasses of water

Vidit Sarkar • Apr 10 '20

I want to suggest a challenge. What should be the subject of my email? Can I send a markdown file?

Brian Bethencourt • Apr 10 '20

Hey Vidit, I'm happy to hear you wanna suggest a challenge. You can send any suggestions to yo+challenge@dev.to. Feel free to drop the content of your challenge in the email, markdown file works too. Subject doesn't matter too much, we'll know what it is.

Take care!

Vidit Sarkar • Apr 10 '20

Thanks!

Alvaro Montoro • Apr 10 '20 • Edited

Using regular expressions in JavaScript:

const hydrate = s => {
  // get an array with all the numbers in the string, and add the values using reduce
  const number = s.match(/\d/g)
                  .reduce((acc, val) => acc + parseInt(val), 0);
  return `${number} glass${number != 1 ? 'es' : ''} of water`;
}

We get the following results:

hydrate("1 beer")
// 1 glass of water 
hydrate("2 glasses of wine and 1 shot")
// 3 glasses of water 
hydrate("1 shot, 5 beers, 2 shots, 1 glass of wine, 1 beer")
// 10 glasses of water

Davyd McColl • Apr 12 '20

I didn't see yours, but mine is practically identical 😮

Alvaro Montoro • Apr 12 '20

Yours has some checks that make it more robust... And that I probably should add to mine 😳

Arnav Motwani • Apr 10 '20

My solution in python

import re
order = input("list the drinks")


def Hydrate(order):
    glasses = 0
    drinks = re.split(", |and ",order)
    for number in drinks:
        tab = number.split(" ")
        glasses += int(tab[0])
    print(glasses)

Hydrate(order)

Rafael Acioly • Apr 13 '20

Python solution 🐍

import re

def drink(order: str) -> str:
    numbers = re.findall('\d+', order)
    amount = sum(int(amount) for amount in numbers)
    return f"{amount} glasses of water"

kesprit • Apr 11 '20 • Edited

My swift solution :

func hydrate(_ input: String) -> String {
    let number = input.split(separator: .init(" "))
        .map { $0.filter { c in c.isNumber } }
        .compactMap { Int($0) }
        .reduce(into: 0) { $0 += $1 }
    return "\(number) glass\(number > 1 ? "es": "") of water"
}

hydrate("1 beer") // 1 glass of water
hydrate("2 glasses of wine and 1 shot") // 3 glasses of water
hydrate("1 shot, 5 beers, 2 shots, 1 glass of wine, 1 beer") // 10 glasses of water

Davyd McColl • Apr 12 '20

function hydrate(sentence) {
  const
    howMany = (sentence.match(/(\d+)/g) || [])
      .reduce((acc, cur) => acc + parseInt(cur), 0),
    s = howMany === 1 ? "" : "es";
    return `${howMany} glass${s} of water`;
}