# Daily Challenge #223 - Responsible Drinking

Welcome to the bar!

We recommend you drink 1 glass of water per drink so you're not hungover tomorrow morning. Your fellow coders have bought you several drinks tonight in the form of strings. Return a string suggesting how many glasses of water you should drink to not be hungover.

If you would like to keep things simple, you can consider any "numbered thing" in the string to be a drink. Even "1 bear" => "1 glass of water" or "1 chainsaw and 2 pools" => "3 glasses of water".

Example Pairs
Input 0:
"1 beer"
Output 0:
"1 glass of water"

Input 1:
"1 shot, 5 beers, 2 shots, 1 glass of wine, 1 beer"
Output 1:
"10 glasses of water"

Tests
hydrate("1 beer")
hydrate("2 glasses of wine and 1 shot")
hydrate("1 shot, 5 beers, 2 shots, 1 glass of wine, 1 beer")

Good luck!

This challenge comes from taylormb on CodeWars. Thank you to CodeWars, who has licensed redistribution of this challenge under the 2-Clause BSD License!

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### Discussion

Python solution

import re

def hydrate(drinks: str) -> str:
drinkCount = sum(map(int, re.findall("\d+", drinks))) # total number of drinks
# this will also work, drinkCount = sum([int(num) for num in drinks.split(" ") if num.isdigit()])

return str(drinkCount) + " glass" + ("es" if drinkCount > 1 else "") + " of water"

print(hydrate("1 beer")) # output -> 1 glass of water
print(hydrate("2 glasses of wine and 1 shot")) # output -> 3 glasses of water
print(hydrate("1 shot, 5 beers, 2 shots, 1 glass of wine, 1 beer")) # output -> 10 glasses of water

I want to suggest a challenge. What should be the subject of my email? Can I send a markdown file?

Hey Vidit, I'm happy to hear you wanna suggest a challenge. You can send any suggestions to yo+challenge@dev.to. Feel free to drop the content of your challenge in the email, markdown file works too. Subject doesn't matter too much, we'll know what it is.

Take care!

Using regular expressions in JavaScript:

const hydrate = s => {
// get an array with all the numbers in the string, and add the values using reduce
const number = s.match(/\d/g)
.reduce((acc, val) => acc + parseInt(val), 0);
return ${number} glass${number != 1 ? 'es' : ''} of water;
}

We get the following results:

hydrate("1 beer")
// 1 glass of water
hydrate("2 glasses of wine and 1 shot")
// 3 glasses of water
hydrate("1 shot, 5 beers, 2 shots, 1 glass of wine, 1 beer")
// 10 glasses of water

I didn't see yours, but mine is practically identical 😮

Yours has some checks that make it more robust... And that I probably should add to mine 😳

My solution in python

import re
order = input("list the drinks")

def Hydrate(order):
glasses = 0
drinks = re.split(", |and ",order)
for number in drinks:
tab = number.split(" ")
glasses += int(tab[0])
print(glasses)

Hydrate(order)

Js vanilla solution (fix below)

What if I drink "11 beers"?

(I have a feeling I'll be severely under-hydrated)

Oh, that's interesting. I'll upload a fix asap. Thanks for reporting!
EDIT: fixed! The problem was the split -not necessary. Also have forgot the existence of reduce! I need a vacation

Your theme looks amazing, what is it?

Thank you! It's a customization I've made from Material Ocean, nothing special :)

Any chance you would be willing to upload it for me somewhere? :)

Well, I could send it to you by email but note that I had customize only the Js, Sass, Css. HTML and Ts parts. Let me know!

Python solution 🐍

import re

def drink(order: str) -> str:
numbers = re.findall('\d+', order)
amount = sum(int(amount) for amount in numbers)
return f"{amount} glasses of water"

My swift solution :

func hydrate(_ input: String) -> String {
let number = input.split(separator: .init(" "))
.map { $0.filter { c in c.isNumber } } .compactMap { Int($0) }
.reduce(into: 0) { $0 +=$1 }
return "\(number) glass\(number > 1 ? "es": "") of water"
}

hydrate("1 beer") // 1 glass of water
hydrate("2 glasses of wine and 1 shot") // 3 glasses of water
hydrate("1 shot, 5 beers, 2 shots, 1 glass of wine, 1 beer") // 10 glasses of water

function hydrate(sentence) {
const
howMany = (sentence.match(/(\d+)/g) || [])
.reduce((acc, cur) => acc + parseInt(cur), 0),
s = howMany === 1 ? "" : "es";
return ${howMany} glass${s} of water;
}