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Daily Challenge #223 - Responsible Drinking

dev.to staff on April 10, 2020

Welcome to the bar! We recommend you drink 1 glass of water per drink so you're not hungover tomorrow morning. Your fellow coders have bought you ...

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Vidit Sarkar • Apr 10 '20

Python solution

import re

def hydrate(drinks: str) -> str:
    drinkCount = sum(map(int, re.findall("\d+", drinks))) # total number of drinks
    # this will also work, drinkCount = sum([int(num) for num in drinks.split(" ") if num.isdigit()])

    return str(drinkCount) + " glass" + ("es" if drinkCount > 1 else "") + " of water"


print(hydrate("1 beer")) # output -> 1 glass of water
print(hydrate("2 glasses of wine and 1 shot")) # output -> 3 glasses of water
print(hydrate("1 shot, 5 beers, 2 shots, 1 glass of wine, 1 beer")) # output -> 10 glasses of water

Vidit Sarkar • Apr 10 '20

I want to suggest a challenge. What should be the subject of my email? Can I send a markdown file?

Brian Bethencourt • Apr 10 '20

Hey Vidit, I'm happy to hear you wanna suggest a challenge. You can send any suggestions to yo+challenge@dev.to. Feel free to drop the content of your challenge in the email, markdown file works too. Subject doesn't matter too much, we'll know what it is.

Take care!

Vidit Sarkar • Apr 10 '20

Thanks!

Alvaro Montoro • Apr 10 '20 • Edited

Using regular expressions in JavaScript:

const hydrate = s => {
  // get an array with all the numbers in the string, and add the values using reduce
  const number = s.match(/\d/g)
                  .reduce((acc, val) => acc + parseInt(val), 0);
  return `${number} glass${number != 1 ? 'es' : ''} of water`;
}

We get the following results:

hydrate("1 beer")
// 1 glass of water 
hydrate("2 glasses of wine and 1 shot")
// 3 glasses of water 
hydrate("1 shot, 5 beers, 2 shots, 1 glass of wine, 1 beer")
// 10 glasses of water

Davyd McColl • Apr 12 '20

I didn't see yours, but mine is practically identical 😮

Alvaro Montoro • Apr 12 '20

Yours has some checks that make it more robust... And that I probably should add to mine 😳

Arnav Motwani • Apr 10 '20

My solution in python

import re
order = input("list the drinks")


def Hydrate(order):
    glasses = 0
    drinks = re.split(", |and ",order)
    for number in drinks:
        tab = number.split(" ")
        glasses += int(tab[0])
    print(glasses)

Hydrate(order)

Rafael Acioly • Apr 13 '20

Python solution 🐍

import re

def drink(order: str) -> str:
    numbers = re.findall('\d+', order)
    amount = sum(int(amount) for amount in numbers)
    return f"{amount} glasses of water"

kesprit • Apr 11 '20 • Edited

My swift solution :

func hydrate(_ input: String) -> String {
    let number = input.split(separator: .init(" "))
        .map { $0.filter { c in c.isNumber } }
        .compactMap { Int($0) }
        .reduce(into: 0) { $0 += $1 }
    return "\(number) glass\(number > 1 ? "es": "") of water"
}

hydrate("1 beer") // 1 glass of water
hydrate("2 glasses of wine and 1 shot") // 3 glasses of water
hydrate("1 shot, 5 beers, 2 shots, 1 glass of wine, 1 beer") // 10 glasses of water

Davyd McColl • Apr 12 '20

function hydrate(sentence) {
  const
    howMany = (sentence.match(/(\d+)/g) || [])
      .reduce((acc, cur) => acc + parseInt(cur), 0),
    s = howMany === 1 ? "" : "es";
    return `${howMany} glass${s} of water`;
}

Tatu Pesonen • Apr 11 '20

Your theme looks amazing, what is it?

Davyd McColl • Apr 12 '20

What if I drink "11 beers"?

(I have a feeling I'll be severely under-hydrated)

Tatu Pesonen • Apr 11 '20

Any chance you would be willing to upload it for me somewhere? :)