Daily Challenge (161 Part Series)
I'm not sure how many of you are familiar with the ancient rice and chessboard problem (Wikipedia calls it wheat for some reason) but here's a quick recap for you: a young person asks, as compensation, only 1 grain of rice for the first square, 2 grains for the second, 4 for the third, 8 for the fourth and so on, always doubling the previous.
Your task is pretty straightforward: Write a function that, given an amount of grain, calculates to which square one needs to land on to reach at least that amount of grain.
As usual, a few examples might be way better than thousands of words from me:
squaresNeeded(grain) === chessboard square
squaresNeeded(0) === 0
squaresNeeded(1) === 1
squaresNeeded(2) === 2
squaresNeeded(3) === 2
squaresNeeded(31) === 5
Input is always going to be valid/reasonable: a non negative number.
squaresNeeded(128) === ?
squaresNeeded(4000000) === ?
squaresNeeded(32768) === ?
Good luck, happy coding!
Want to propose a challenge idea for a future post? Email email@example.com with your suggestions!