# Daily Challenge #281 - Area or Perimeter

You are given the length and width of a 4-sided polygon. The polygon can either be a rectangle or a square.

If it is a square, return its area. If it is a rectangle, return its perimeter.

area_or_perimeter(6, 10) --> 32
area_or_perimeter(4, 4) --> 16

### Tests

area_or_perimeter(5, 5)
area_or_perimeter(10, 20)

Good luck!

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### Discussion

learning Go

func area_or_perimeter(x int, y int) int {
if x == y {
return x * y
} else {
return 2 * (x + y)
}
}

func main() {
//tests
fmt.Println(area_or_perimeter(5, 5))
fmt.Println(area_or_perimeter(10, 20))
}

def area_or_perimeter(a, b):
if a == b:
return a * b
else:
return 2 * (a + b)

assert area_or_perimeter(5, 5) == 25
assert area_or_perimeter(10, 20) == 60

return a * b if a == b else 2 * (a + b)

:)

Here is the simple solution with Python:

def area_or_perimeter(l , w):
if l == w:
return l * w
return (l + w) * 2

mov     rcx, rsi
imul    rcx, rdi
lea     rax, [rsi + rdi]
cmp     rdi, rsi
cmove   rax, rcx
ret

ooga booga

In Kotlin it would be:

fun area_or_perimeter(a: Int, b: Int) =
if (a == b)
a * b
else
2 * (a + b)

def area_or_perimeter(l,w):
return l*w if l==w else 2*(l+w)

const area_or_perimeter = (a,b) => a===b ? a*b : 2*(a+b);

In js: let area_or_perimeter = (x, y) => x === y ? x*y : 2*(x+y);

Pass all the tests.

A solution in Forth:

: area-or-perimeter 2dup = if * else + 2 * then ;
4 4 area-or-perimeter . 16  ok
6 10 area-or-perimeter . 32  ok

It's quite simple, check whether a=b if it's true return a*b if it's not, return (a+b)*2.