Daily Challenge (245 Part Series)
Implement a function to calculate the growth of a population of people. The function should be able to take several parameters, including
aug(inhabitants coming or leaving each year), and
p(population to surpass). This function should output n(number of years needed to get a population of
Don't forget to convert the percent parameter as a percentage in the body of your function: if the parameter percent is 2 you have to convert it to 0.02.
In our example, the population is p0 = 1000 at the beginning of a year. The population regularly increases by 2 percent per year and moreover 50 new inhabitants per year come to live in the town.
How many years need to pass for the town to see its population greater or equal to p = 1200 inhabitants?
At the end of the first year there will be: 1000 + 1000 * 0.02 + 50 => 1070 inhabitants At the end of the 2nd year there will be: 1070 + 1070 * 0.02 + 50 => 1141 inhabitants (number of inhabitants is an integer) At the end of the 3rd year there will be: 1141 + 1141 * 0.02 + 50 => 1213 It will need 3 entire years.
nbYear(1500, 5, 100, 5000)
nbYear(1500000, 2.5, 10000, 2000000)
nbYear(1500000, 0.25, 1000, 2000000)
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