Given the roots of two binary trees root and subRoot, return true if there is a subtree of root with the same structure and node values of subRoot and false otherwise.
A subtree of a binary tree tree is a tree that consists of a node in tree and all of this node's descendants. The tree tree could also be considered as a subtree of itself.
Example 1:
Input: root = [3,4,5,1,2], subRoot = [4,1,2]
Output: true
Example 2:
Input: root = [3,4,5,1,2,null,null,null,null,0], subRoot = [4,1,2]
Output: false
Constraints:
- The number of nodes in the
roottree is in the range[1, 2000]. - The number of nodes in the
subRoottree is in the range[1, 1000]. -
-104 <= root.val <= 104 -
-104 <= subRoot.val <= 104
SOLUTION:
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def isSameTree(self, p: Optional[TreeNode], q: Optional[TreeNode]) -> bool:
if not p or not q:
if p or q:
return False
return True
if p.val == q.val and self.isSameTree(p.left, q.left) and self.isSameTree(p.right, q.right):
return True
def isSubtree(self, root: Optional[TreeNode], subRoot: Optional[TreeNode]) -> bool:
if self.isSameTree(root, subRoot):
return True
if not root or not subRoot:
return False
return self.isSubtree(root.left, subRoot) or self.isSubtree(root.right, subRoot)
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