Average Salary Excluding the Minimum and Maximum Salary

You are given an array of unique integers salary where salary[i] is the salary of the ith employee.

Return the average salary of employees excluding the minimum and maximum salary. Answers within 10-5 of the actual answer will be accepted.

Example 1:

Input: salary = [4000,3000,1000,2000]
Output: 2500.00000
Explanation: Minimum salary and maximum salary are 1000 and 4000 respectively.
Average salary excluding minimum and maximum salary is (2000+3000) / 2 = 2500

Example 2:

Input: salary = [1000,2000,3000]
Output: 2000.00000
Explanation: Minimum salary and maximum salary are 1000 and 3000 respectively.
Average salary excluding minimum and maximum salary is (2000) / 1 = 2000

Constraints:

• 3 <= salary.length <= 100
• 1000 <= salary[i] <= 106
• All the integers of salary are unique.

SOLUTION:

class Solution:
    def average(self, salary: List[int]) -> float:
        n = len(salary)
        total = 0
        currmin = float('inf')
        currmax = float('-inf')
        for i in range(n):
            currmin = min(currmin, salary[i])
            currmax = max(currmax, salary[i])
            total += salary[i]
        return (total - currmin - currmax) / (n - 2)