Implement pow(x, n), which calculates x raised to the power n (i.e., xn).
Example 1:
Input: x = 2.00000, n = 10
Output: 1024.00000
Example 2:
Input: x = 2.10000, n = 3
Output: 9.26100
Example 3:
Input: x = 2.00000, n = -2
Output: 0.25000
Explanation: 2-2 = 1/22 = 1/4 = 0.25
Constraints:
-
-100.0 < x < 100.0 -
-231 <= n <= 231-1 -
-104 <= xn <= 104
SOLUTION:
class Solution:
def myPow(self, x: float, n: int) -> float:
if n < 0:
return 1 / self.myPow(x, -n)
if n == 0:
return 1
if n % 2 == 0:
curr = self.myPow(x, n // 2)
return curr * curr
else:
curr = self.myPow(x, (n - 1) // 2)
return x * curr * curr
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