# #37 - Row of the odd triangle - CodeWars Kata (6 kyu)

## Instructions

Given a triangle of consecutive odd numbers:

``````               1
3     5
7     9    11
13    15    17    19
21    23    25    27    29
``````

find the triangle's row knowing its index (the rows are 1-indexed), e.g.:

odd_row(1) == 
odd_row(2) == [3, 5]
odd_row(3) == [7, 9, 11]

Note: your code should be optimized to handle big inputs.

## My solution:

``````function oddRow(n) {
let first = 1;
for(let i = 1; i<n; i++){
first+=i*2
}

let r = [first];
for(let i = 1; i<n; i++){
r.push(first+=2)
}

return r
}
``````

## Explanation

First I got the first value of the row that I'm searching on, I did this by using a for loop that will iterate the number of rows, and in every iteration I changed the value of the var "first" by adding 2 to it and revaluing it.

``````  for(let i = 1; i<n; i++){
first+=i*2
}
``````

After that with that value I made the variable "r" that will contain the result that will be returned, inside of it I stored the first number of the row

``````let r = [first];
``````

After that I used another loop and inside of it, I pushed every value after the first plus 2, and at the end I just returned "r"

``````for(let i = 1; i<n; i++){
r.push(first+=2)
}

return r
``````