I know I can not be on even top 1000 but I love to solve challenges. Lets share your solution too. And the solution to day 8 is not that harder but kind of brute force has to be done. Link to the challenge is here. I have updated my notebook at this repository.
with open("day8.txt", "r") as fp: lines = fp.readlines() lines = [line.rstrip() for line in lines] # print(lines) # challenge 1 def challenge1(lines): curr_acc = 0 visited_line = set() curr_line = 0 valid_sol = True while True: # viewed all lines and we got lucky, no loops if len(lines)-1 == curr_line: valid_sol = False # for challenge 1 solution if curr_line in visited_line: valid_sol = False return curr_acc, valid_sol inst, acc = lines[curr_line].split(" ") acc = int(acc) visited_line.add(curr_line) if inst == "nop": curr_line += 1 if inst == "acc": curr_acc += acc curr_line += 1 if inst == "jmp": curr_line+=acc # we got lucky if valid_sol == False: return curr_acc, True return curr_acc, False print("Current Accumulator: ", challenge1(lines)) # challenge 2 def challenge2(lines): curr_acc = 0 visited_line =  curr_line = 0 new_lines = lines.copy() for curr_line in range(1, len(new_lines)): inst, acc = lines[curr_line].split(" ") acc = int(acc) if inst == "nop": inst = "jmp" elif inst == "jmp": inst = "nop" visited_line =  new_lines = lines.copy() new_lines[curr_line] = " ".join((inst, str(acc))) acc, valid = challenge1(new_lines) if valid: return acc print("Current Accumulator: ", challenge2(lines))
I write blogs about Computer Vision projects on my GitHub page q-viper.github.io and if you got some time please share yours too.
Top comments (2)
Found a very similar solution:
I never learned how to write shorter codes. Thanks for sharing. Your solution is neat.