What is a value object?
A small simple object, like money or a date range, whose equality isn't based on identity.
Martin Fowler
Objects in Ruby are usually considered to be entity objects. Two objects may have matching attribute values but we do not consider them equal because they are distinct objects.
In this example a
and c
are not equal:
class Panserbjorn
def initialize(name)
@name = name
end
end
a = Panserbjorn.new('Iorek')
b = Panserbjorn.new('Iofur')
c = Panserbjorn.new('Iorek')
a == c #=> => false
# Three distinct objects:
a.object_id #=> 70165973839880
b.object_id #=> 70165971554200
c.object_id #=> 70165971965460
Value objects on the other hand, are compared by value. Two different value objects are considered equal when their attribute values match.
Symbol
, String
, Integer
and Range
are examples of value objects in Ruby.
Here, a
and c
are considered equal despite being distinct objects:
a = 'Iorek'
b = 'Iofur'
c = 'Iorek'
a == b #=> false
a == c #=> true
# Three distinct objects:
a.object_id #=> 70300461022500
b.object_id #=> 70300453210700
c.object_id #=> 70300461053840
How can I create a value object?
Say I want a class to represent the days of the week and I also want instances of that class to be considered equal if they represent the same day. A Sunday object should equal another Sunday object. A Monday object should equal another Monday object, etc…
I might begin with the following class:
class DayOfWeek
DAYS = {
1 => 'Sunday',
2 => 'Monday',
3 => 'Tuesday',
4 => 'Wednesday',
5 => 'Thursday',
6 => 'Friday',
7 => 'Saturday'
}.freeze
def initialize(day)
raise ArgumentError, 'Day outside range' unless (1..7).cover?(day)
@day = day
end
def to_i
day
end
def to_s
DAYS[day]
end
private
attr_accessor :day
end
Now, I am going to instantiate three objects to represent the days of the week on which I eat pizza, pay the milk man, and put out the recycling for collection:
pizza_day = DayOfWeek.new(5)
milk_money_day = DayOfWeek.new(2)
recycling_collection_day = DayOfWeek.new(5)
I know that I eat pizza for dinner the same day that I put out the recycling. I consider these objects to represent the same thing: Thursday. They should be equivalent. But they're not:
pizza_day == recycling_collection_day #=> false
That's because they're not yet value objects. #==
compares the identities of the objects.
I should override #==
. I will use pry to find out where the method comes from so we can see how it derives its current behaviour.
pizza_day.method(:==).owner #=> BasicObject
DayOfWeek
inherits #==
from BasicObject
.
The page for BasicObject#==
states:
== returns true only if obj and other are the same object. Typically, this method is overridden in descendant classes to provide class-specific meaning.
Aha! The class specific meaning in this case is I want to compare its instances by value.
I know that these objects expose an integer. It makes sense to compare against that but I don't want to compare a day with an actual integer. Thursday should not be equivalent to the number 5.
I also know that a DayOfWeek
exposes a string as well. It follows that any equivalent days would return matching string and integer values:
class DayOfWeek
# ...
def ==(other)
to_i == other.to_i &&
to_s == other.to_s
end
alias eql? ==
# ...
end
I have aliased #eql?
to #==
. The BasicObject
documentation explains:
For objects of class Object, eql? is synonymous with ==. Subclasses normally continue this tradition by aliasing eql? to their overridden ==
Bingo! We have value objects. pizza_day
and recycling_collection_day
are considered equivalent:
pizza_day == recycling_collection_day #=> true
I could override other comparison methods, <=
, <
, ==
, >=
, >
and between?
as it makes sense to say that Monday
is less than Tuesday
or Friday
is greater than Thursday
but I have decided that's not needed for now.
There is however, one more important step that I need to implement. These objects are equivalent, so when used as a hash key I would expect them to point to the same bucket.
The Hash
documentation suggests:
Two objects refer to the same hash key when their hash value is identical and the two objects are eql? to each other.
A user-defined class may be used as a hash key if the hash and eql? methods are overridden to provide meaningful behavior. By default, separate instances refer to separate hash keys.
Following that advice, I need to change the default behaviour of #hash
. I already know that integers in Ruby are value objects. I can see that equivalent integers always return the same #hash
.
a = 1
b = 1
a.object_id #=> 3
b.object_id #=> 3
1.object_id #=> 3
1.hash == 2.hash #=> false
[a,b,1].map(&:hash).uniq.count #=> 1
101.hash == (100 + 1).hash #=> true
The same goes for strings:
a = 'Svalbard'
b = 'Svalbard'
# Note the different object ids:
a.object_id #=> 70253833847520
b.object_id #=> 70253847146940
'Svalbard'.object_id #=> 70253847210020
# The hash values of equivalent strings match:
'Svalbard'.hash == 'Bolvanger'.hash #=> false
[a,b,"Svalbard"].map(&:hash).uniq.count #=> 1
'Svalbard'.hash == ('Sval' + 'bard').hash #=> true
I will generate the hash using its string and integer properties.
def ==(other)
to_i == other.to_i
end
alias eql? ==
def hash
to_i.hash ^ to_s.hash
end
Per the example in the documentation, I've used the XOR operator (^
) to derive the new hash value.
Now that I have overridden #hash
, I can see that equivalent DayOfWeek
instances point to the same bucket:
day_1 = DayOfWeek.new(1)
day_2 = DayOfWeek.new(1)
day_1 == day_2 #=> true
notes = {} #=> {}
notes[day_1] = 'Rest'
notes[day_2] = 'Party'
notes.length #=> 1
notes #=> {#<DayOfWeek:0x00007fa193e44170 @day=1>=>"Party"}
Structs
If I want multiple value objects, I might have to override #hash
and #==
for each class.
I could decide to use structs instead.
A Struct is a convenient way to bundle a number of attributes together, using accessor methods, without having to write an explicit class.
Structs are value objects by default. Of course we now have an idea of how this works. The documentation explains:
Equality—Returns true if other has the same struct subclass and has equal member values (according to Object#==).
Just as we thought!
DayOfWeek = Struct.new(:day) do
DAYS = {
1 => 'Sunday',
2 => 'Monday',
3 => 'Tuesday',
4 => 'Wednesday',
5 => 'Thursday',
6 => 'Friday',
7 => 'Saturday'
}.freeze
def to_s
DAYS[day]
end
def to_i
day
end
end
a = DayOfWeek.new(1)
b = DayOfWeek.new(2)
c = DayOfWeek.new(1)
a == c #=> true
a == b #=> false
Summary
We now know the difference between an entity object and a value object. We have learned that we need to override both #hash
and #==
if our value objects are to be used as hash keys. And, we have learned that structs provide value object behaviour straight out of the box.
Top comments (3)
You can also include the
Comparable
module and just implement a single spaceship operator method and all comparison classes would work.See doc here: docs.ruby-lang.org/en/2.5.0/Compar...
Thank you. That had slipped from my radar. Yes,
Comparable
gives me<
,<=
etc... just by defining<==>
:Yes, a lot more convenient. Thanks. I wish I'd known about it before.