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Arrow Function and The new, arguments & super Keyword!

bhagatparwinder profile image Parwinder 👨🏻‍💻 ・2 min read

We learned about arrow functions and how it behaves differently with this keyword.

Arrow functions behave differently when it comes to this keyword. It also has no bindings to arguments, new, and super keyword!

Arguments

The arguments object is an Array-like object that allows us to access all the arguments passed to a function.

function addThreeNumbers(a, b, c) {
    console.log(arguments.length); // 3
    console.log(arguments[0]); // 4
    console.log(arguments[1]); // 17
    console.log(arguments[2]); // 22
    return a + b + c;
}

console.log(addThreeNumbers(4, 17, 22)); // 43

arguments for arrow functions is a reference to the arguments of the enclosing scope instead.

const bar = x => console.log(arguments);

console.log(bar()); // Uncaught ReferenceError: arguments is not defined

We can solve this "problem" with a workaround. Use the rest operator when you need access to arguments.

const addThreeNumbers = (...args) => {
    console.log(args.length); // 3
    console.log(args[0]); // 4
    console.log(args[1]); // 17
    console.log(args[2]); // 22
    return args[0] + args[1] + args[2];
}

console.log(addThreeNumbers(4, 17, 22)); // 43

You can make the above example a bit cleaner using destructuring.

const addThreeNumbers = (...args) => {

    const [a, b, c] = args;

    console.log(args.length); // 3
    console.log(a); // 4
    console.log(b); // 17
    console.log(c); // 22

    return a + b + c;
}

console.log(addThreeNumbers(4, 17, 22)); // 43

New

Arrow functions cannot be used as constructors. new will throw an error when used with arrow functions.

const foo = () => { };
const bar = new foo(); // foo is not a constructor

Arrow functions are missing a Construct internal method.

Super

We cannot use the super keyword with arrows either per ES spec.

class Base {
    public foo = () => {
        console.log("Hello");
    }
}

class Child extends Base {
    public bar() {
        super.foo(); // Only public and protected methods of the base class are accessible via the 'super' keyword.
    };
}

Instead, use regular functions in such a case.

class Base {
    public foo() {
        console.log("Hello");
    }
}

class Child extends Base {
    public bar() {
        super.foo();
    };
}

Bonus 🤑

  • Arrow functions do not have a prototype property.
   var Foo = () => { };
   console.log(Foo.prototype); // undefined
  • Arrow functions cannot be used as generators. They do not have a yield keyword.

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