** Shifted Array Search **

A sorted array of distinct integers shiftArr is shifted to the left by an unknown offset and you don’t have a pre-shifted copy of it. For instance, the sequence 1, 2, 3, 4, 5 becomes 3, 4, 5, 1, 2, after shifting it twice to the left.

Given shiftArr and an integer num, implement a function shiftedArrSearch that finds and returns the index of num in shiftArr. If num isn’t in shiftArr, return -1. Assume that the offset can be any value between 0 and arr.length - 1.

Explain your solution and analyze its time and space complexities.

**Example**

```
input: shiftArr = [9, 12, 17, 2, 4, 5], num = 2 # shiftArr is the
# outcome of shifting
# [2, 4, 5, 9, 12, 17]
# three times to the left
output: 3 # since it’s the index of 2 in arr
```

## Top comments (2)

Here is a Python solution,

Test cases,

if(num >= arr[low] and num < arr[mid]):

In equal case, you should return 'low' , there is no need to do anything.