Why function deceleration overrides

kambala yashwanth on November 30, 2018

var myName = "Richard"; function myName () { console.log ("Rich"); } console.log(typeof myName) ////output is string but when i code fu... [Read Full]
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What's happening here is that you've hit the difference between a function expression and function declaration.

function myName () {
console.log ("Rich");

This is a function declaration, and it is subject to a javascript feature called hoisting, which moves it to the top of the scope it's declared in. This means that when you set var myName = "Richard", it actually comes afterwards in the order of execution and overwrites the function.

By contrast, myName = function() { ... } is a function expression, and it is evaluated in place, and behaves as you'd expect with your code laid out as it is.

I actually just wrote a post on this exact thing -- carlanderson.xyz/function-declarat...


It's already explained but you are re-assigning your name variable (the string) to the function.

I'd do this:

// Good :D

const myName = 'Richard'; 

const logMyName = () => {

This example below will throw an 
error because you can't re-assign 
a constant variable so use the 
one I wrote above :)

// Bad :(

myName = () => {
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