DESCRIPTION:
Compare two arrays and return a new array with any items only found in one of the two given arrays, but not both. In other words, return the symmetric difference of the two arrays.
Examples
[1, 2, 3, 5], [1, 2, 3, 4, 5]
// should return [4].
[1, "calf", 3, "piglet"], [1, "calf", 3, 4]
// should return ["piglet", 4].
My approach for solving this problem:
- concat the 2 arrayes.
- add every item into new obj
- if it's unquie get vlaue of 1 and get 2 if it's not.
- if not return sliced str with num length.
- filter item with value of 1 then map the number.
My solution:
function diffArray(arr1, arr2) {
let newArr = arr1.concat(arr2)
let numObj = {}
newArr.forEach((item)=>{
numObj[item] = numObj[item] ? numObj[item] +1:1
})
return Object.keys(numObj)
.filter((item)=>{
return numObj[item] == 1
})
.map((num)=>{
if(!isNaN(num)){
return +num
}
return num
})
}
diffArray([1, "calf", 3, "piglet"], [1, "calf", 3, 4]);
freeCodeCamp approach for solving this problem:
- concat the 2 arrays.
- filter if item includes in arr1 or arr2 and return him.
freeCodeCamp solution:
function diffArray(arr1, arr2) {
return arr1
.concat(arr2)
.filter(item => !arr1.includes(item) || !arr2.includes(item));
}
diffArray([1, "calf", 3, "piglet"], [1, "calf", 3, 4]);
Any tips or edit are most welcome. share it with me on the comments. Thanks for being here!
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Any tips or edit are most welcome. share it with me on the comments. Thanks for being here!