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Let's solve freeCodeCamp's intermediate algorithm scripting challenge, 'Map the Debris'.
Starter Code
function orbitalPeriod(arr) {
var GM = 398600.4418;
var earthRadius = 6367.4447;
return arr;
}
orbitalPeriod([{name : "sputnik", avgAlt : 35873.5553}]);
Instructions
Return a new array that transforms the elements' average altitude into their orbital periods (in seconds).
The array will contain objects in the format {name: 'name', avgAlt: avgAlt}
.
You can read about orbital periods on Wikipedia.
The values should be rounded to the nearest whole number. The body being orbited is Earth.
The radius of the earth is 6367.4447 kilometers, and the GM value of earth is 398600.4418 km3s2.
Test Cases

orbitalPeriod([{name : "sputnik", avgAlt : 35873.5553}])
should return[{name: "sputnik", orbitalPeriod: 86400}]
. 
orbitalPeriod([{name: "iss", avgAlt: 413.6}, {name: "hubble", avgAlt: 556.7}, {name: "moon", avgAlt: 378632.553}])
should return[{name : "iss", orbitalPeriod: 5557}, {name: "hubble", orbitalPeriod: 5734}, {name: "moon", orbitalPeriod: 2377399}]
.
Our Approach
The instructions for this challenge are short and to the point.
Our input is an array of one or more objects.
We have to return the same array of objects, but altering one of the keyvalue pairs (
avgAlt
>orbitalPeriod
).Make sure orbitalPeriod is calculated in seconds and rounded up to the nearest whole number.
The last challenge seems a bit hard. This formula is a little complex. But basically we have to do some math to calculate it, deleted avgAlt
, and add in orbitalPeriod
into each object in the array.
After a lot of Internet searching (formerly known as Googling  I don't like to feed into the search engine bias), I came across the correct formula, T = 2 * pi * sqrt(r^3/GM); r = earthRadius + avgAlt
.
GM is provided in the instructions, as is the radius of the Earth. We can start by setting those variables.
const GM = 398600.4418;
const earthRadius = 6367.4447;
Now that we have our values and a formula, we can plug in those values and do some math. Once we have the orbital period value, we can add it to each object, and remove the avgAlt
. We can loop over each object in the array using map()
.
arr.map(obj => {
let oP = Math.round(2 * Math.PI * Math.sqrt(Math.pow(earthRadius + obj.avgAlt, 3) / GM));
// More stuff
})
So we set a variable with the above formula. We use Math.round()
as the instructions wanted us to round to the nearest whole number. Next we can delete avgAlt
as we have used it in the formula. Then we can add oP
to the object.
arr.map(obj => {
let oP = Math.round(2 * Math.PI * Math.sqrt(Math.pow(earthRadius + obj.avgAlt, 3) / GM));
// Delete avgAlt
delete obj.avgAlt;
// Add orbitalPeriod
obj.orbitalPeriod = op;
})
We have updated the object(s) in arr
. Lastly, we want to make sure to return arr
.
Our Solution
function orbitalPeriod(arr) {
var GM = 398600.4418;
var earthRadius = 6367.4447;
arr.map(obj => {
let oP = Math.round(2 * Math.PI * Math.sqrt(Math.pow(earthRadius + obj.avgAlt, 3) / GM));
delete obj.avgAlt;
obj.orbitalPeriod = oP;
})
return arr;
}
Links & Resources
'Map the Debris' Challenge on fCC
Thank you for reading!
Top comments (1)
thank you for the explanation