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Daily Challenge #212 - DNA to RNA

dev.to staff on March 25, 2020

Deoxyribonucleic acid, DNA is the primary information storage molecule in biological systems. It is composed of four nucleic acid bases Guanine ('G...

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@nobody • Mar 25 '20

Super simple! I love the polyglot answers 👌🏿
Clojure

(ns dailyChallenge.206)

(def- NUCLEOTIDES
  "Valid Nucleotides"
  (re-pattern "G|C|T|A|U"))

(defn DNA->RNA [sequence] 
  "validates and converts DNA pairs to RNA"
 {:pre [(!= "" (re-match NUCLEOTIDES (uppercase sequence))]}
  ;;Java.String method interop
  (.toUpperCase (replace sequence #"t|T" "u")))

bravemaster619 • Mar 25 '20

Ruby

def DNAtoRNA(dna)
  reg_dna = /^(G|C|A|T)*$/i
  if dna.match(reg_dna)
    dna.gsub(/(T|t)/, 'U').upcase
  else
    raise "Not a valid DNA string"
  end
end

JavaScript

const DNAtoRNA = (dna) => {
   const dnaRegex = /^(G|C|A|T)*$/gi
   if (dnaRegex.test(dna)) {
      return dna.replace(/t/gi, 'U').toUpperCase()
   } else {
      throw new Error("Not a valid DNA string")
   }
}

PHP

function DNAtoRNA($dna) {
    $dnaRegex = "/^(G|C|A|T)*$/i";
    if (preg_match($dnaRegex, $dna)) {
        return strtoupper(str_ireplace("T", "U", $dna));
    } else {
        throw new \Exception("Not a valid DNA string");
    };
}

Mihail Malo • Mar 26 '20 • Edited

Roost

fn dtoa(dna: &str) -> String {
    dna.chars().map(|c| match c {
        'G' | 'C' | 'A' => c,
        'T' => 'U',
        _ => panic!("you did this to yourself"),
    }).collect()
}
fn main() {
    for x in &["TTTT", "GCAT", "GACCGCCGCC", "💩"] {
        println!("{}=>{}", x, dtoa(x));
    }
}

"Rust"

use itertools::Itertools; // 0.9.0

#[derive(Debug)]
enum DToAError {
    Scat(usize, char),
}
use DToAError::*;

impl std::fmt::Display for DToAError {
    fn fmt(&self, f: &mut std::fmt::Formatter) -> std::fmt::Result {
        match self {
            Scat(i, c) => write!(f, "Is this a joke? At index {}, what is `{}`?! No you can't \"have the processed values back\", get out!", i, c),
        }
    }
}

impl std::error::Error for DToAError {
    fn source(&self) -> Option<&(dyn std::error::Error + 'static)> {
        None
    }
}

fn dtoa(dna: &str) -> Result<String, DToAError> {
    dna.chars()
        .enumerate()
        .map(|(i, c)| {
            Ok(match c {
                'G' | 'C' | 'A' => c,
                'T' => 'U',
                _ => return Err(Scat(i, c)),
            })
        })
        .fold_results(String::with_capacity(dna.len()), |mut s, c| {
            s.push(c);
            s
        })
}
fn main() {
    for x in &["TTTT", "GCAT", "GACCGCCGCC", "💩"] {
        match dtoa(x) {
            Ok(res) => println!("{}=>{}", x, res),
            Err(err) => println!("{}=>OOPS: {}", x, err),
        }
    }
}

It works lol

When you don't listen at all

fn main() {
    for x in &["TTTT", "GCAT", "GACCGCCGCC", "💩"] {
        println!("{}=>{}", x, x.replace('T', "U"))
    }
}

Mark vd Sman • Mar 26 '20

I wanted to see what this challenge was about, because I like these combinations of combined fields. So nice to see this come by!
But I am uncomfortable with the fact that this is not the correct way to code transcription (DNA to RNA). RNA is complementary to DNA because it is double-stranded: therefore GCAT should result in CGUA (on a side note: direction is also very important).

I'm curious if there is any particular reason why it is done in the way you described it?

James • Mar 25 '20 • Edited

Javascript solution:

function DNAtoRNA(dna) {
  return dna.replace(/T/g, 'U');
}

Vidit Sarkar • Mar 25 '20

Python solution

DNAtoRNA = lambda dna : dna.replace('T','U')

Nilbert • Mar 26 '20

Ruby

DNAtoRNA = ->(str) { str.gsub!(/T/,'U')}
DNAtoRNA.call('TTTT')
=> "UUUU"
DNAtoRNA.call('GCAT')
=> "GCAU"

Amin • Mar 25 '20

Elm

dnaToRna : String -> String
dnaToRna = String.replace "T" "U"

Ryan Burmeister-Morrison • Mar 26 '20 • Edited

Ruby

def DNAToRNA(str); str.gsub(/T/i, 'U') end

Vidit Sarkar • Mar 25 '20

C++ solution

string DNAtoRNA(string dna){
    replace(dna.begin(),dna.end(),'T','U');
    return dna;
}

kesprit • Mar 30 '20

My Swift solution :

func DNAtoRNA(string: String) -> String {
    String(string.map { $0 == "T" ? "U" : $0 })
}