# What the Hex!? (how to generate random hex color codes in javascript)

For my most recent Flatiron School project, I wanted to be able to programmatically change the background color of one of the elements on the page, at random. What I needed was a reusable function that I could call `onclick` of various elements on the page. Here are two ways I found to make this happen:

First, I knew I didn't want to have to store a bunch of set colors anywhere. It would be tedious to maintain an array or object filled with set color codes, and I wanted the color selection to be truly random. I decided on using hexadecimal color codes because they are relatively short, and the data needed to comprise them (numbers 0-9, and letters a-f) wouldn't take up too much space. This is how I came up with my initial (somewhat "lazy") solution.

First, we create an array of all possible hexadecimal digits:

``````const digits = [0,1,2,3,4,5,6,7,8,9,'a','b','c','d','e','f']
``````

Then, we need to setup our base hex code string:

``````let hexCode = "#"
``````

We set up a string with the hash/octothorpe ready to go, so we can just append the digits to the string.

Then, we need to choose a hexadecimal digit from the array, at random. To do that we use `Math.round()`, and `Math.random()` to get a randomly selected index of the array. Once we have that digit, we append it onto our hexCode string until the string is 7 characters long (6 digits + the hash/octothorpe), since hex color codes are 6 digits long:

``````while( hexCode.length < 7 ){
hexCode += digits[ Math.round( Math.random() * digits.length ) ]
}
``````

We multiply `Math.random()` by `digits.length` (or the number of items in the `digits` array) because the `Math.random()` function returns a float between 0 and 1. By multiplying that number by the number of items in `digits`, we ensure that we'll always get a float that is anywhere between 0 and the total number of items in the array. We wrap this function in `Math.round()` to round the returned float to the nearest whole number, which makes the total number inclusive of 0 and the total length of the array. We then use this random whole number as the index to select in the `digits` array.

Once we've done this, we just need to `return hexCode`, and our final function looks like this:

``````function generateRandomHexCode(){
const digits = [0,1,2,3,4,5,6,7,8,9,'a','b','c','d','e','f']

let hexCode = "#"

while( hexCode.length < 7 ){
hexCode += digits[ Math.round( Math.random() * digits.length ) ]
}

return hexCode
}
``````

Here are some sample outputs of this function:

``````> generateRandomHexCode()
'#fd88d4'
> generateRandomHexCode()
'#349cba'
> generateRandomHexCode()
'#43a29e'
> generateRandomHexCode()
'#1a1d94'
``````

This works exactly as we need! But after coming up with this solution, I still wondered if there was a more programmatic way to generate a hexadecimal digit, and it turns out there is!

First, let's talk about how hexadecimal (or base 16) digits work. A hexadecimal digit includes decimal numbers 0-9, and the letters a-f. These correspond to the decimal (or base 10) digits 0-15. Here's a quick chart:

So, if we can find a way to convert a decimal to another number base, all we need to do is generate a random number from 0-15 and convert it to base 16. In JavaScript, we can quickly and easily convert a number to another number base using the `.toString()` method, and passing in the base digit.

For example, we can convert numbers to binary using `.toString(2)`

``````  > (10).toString(2)
'1010'

/* if you do not pass the number to `.toString()`
inside of parentheses you will get a syntax error */
``````

Let's see what happens when we try this with a few decimal numbers, converted to base 16:

``````  > (0).toString(16)
'0'
> (11).toString(16)
'b'
> (5).toString(16)
'5'
> (15).toString(16)
'f'
``````

Perfect! That's exactly what we expected, and what we need!

Using this knowledge we can convert our hex code randomizing function as follows:

``````  function generateRandomHexCode() {
let hexCode = "#"

while ( hexCode.length < 7 ) {
hexCode += (Math.round(Math.random() * 15)).toString(16)
}

return hexCode
}
``````

In this version of the function we use `Math.round()` and `Math.random() * 15` to generate a random number between 0 and 15, and then convert that number to its hexadecimal equivalent using `.toString(16)`, and append that newly generated digit to the `hexCode` base until we have 6 digits.

And here are a few of the resulting hex codes:

``````  > generateRandomHexCode()
'#d5758c'
> generateRandomHexCode()
'#26711b'
> generateRandomHexCode()
'#8deca6'
> generateRandomHexCode()
'#3df62c'
> generateRandomHexCode()
'#1a293a'
``````

Excellent!

You can use this output to update the `color` (or `backgroundColor`) of and element in your projects, using something like the following:

``````  someElement.style.backgroundColor = generateRandomHexCode()
``````

You can see this code in action in the CodePen below.

Let me know if there are other hex code generating methods you know of, and definitely let me know if you try this out in your own projects!

xx Emily/@thecodepixi Khauri • Edited on

Nice work! I love seeing the thought processes behind figuring out how to make code better. It's like watching someone piece together a mystery in front of you.

I'm sure you know this as well, but for anyone who doesn't, if you prefix a number with `0x` you can use hex values in your code. (There's also `0b` for binary and `0o` for octal).

Something else to note is that when using Math.floor1 since `Math.random` generates a random number between 0 and 1, but never exactly 1, you have to add 1 to your maximum or else it will never generate that value. So in this case, you should go up to `16` or you'll never get the value `f`:

``````Math.floor(Math.random() * 16)
// or
Math.floor(Math.random() * 0x10)
``````

1 I didn't read the article well enough and assumed `Math.floor` was being used Emmy | Pixi

Thanks, Khauri! I actually didn't know about the `0x` thing. That's super cool! And ++ to the Math.floor() point. It's one of those things I always forget. I used Math.round() in its place but do know that that's not the best solution. Emmy | Pixi • Edited on

Yeah someone else pointed this out to me. Math.floor vs Math.round is one of those things I always forget. Also, excellent work on the alt method! Just as a note, with that solution, it is possible you will get hex codes that are less than 6 digits in length, which won't work as color codes. You'll still need a way to check for the length of the code. Pachi 🪐 (she/her/ela)

Just wanted to say I am proud of you for writing this post!
It is great and I must go do something similar now 😂 maybe with cats 🤔 Pachi 🪐 (she/her/ela)

O M G !!! How do I do colorful cats? Idk but I must find out! Emmy | Pixi

I have no idea but I believe in your ability to figure it out haha Pachi 🪐 (she/her/ela)

Thank you for your trust! 🌈😽😼 Emmy | Pixi

Just to clarify, in the article, the intention is to generate individual digits and convert them to hex one at a time until you have a string of 6 hexadecimal digits. If you just generate any decimal number between 0 and 16777215 and then convert that number to hexadecimal, it will sometimes output hexadecimal numbers shorter than 6 digits (i tested and got a few 4 and 5 digit results) which cannot be used as a hex color code and will cause the function to break if used to assign a code to an element on the page. You still need a way to check for length of 6 on your output. That said, your code does work a lot of the time. But sometimes it doesn't. For me, it broke about 1/20 times when I tested it. Corey McCarty

You could also scale your random by the max value #ffffff and you wouldn't need a loop. Emmy | Pixi

Someone else pointed this out, and it does work quite often, but you do still need to check for a length of 6 on your output for it to be a valid hex color code. Testing that code, it does occasionally output numbers of 4 or 5 digits in length which will break the intended functionality. Corey McCarty

I believe that there is a function to pad the left side of the string with zeroes up to a given length (or you could do it yourself)