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LeetCode "Letter Combinations of a Phone Number"

takakd profile image Takahiro Kudo ・1 min read

I thought of separating the process of combinations is a good approach.

Letter Combinations of a Phone Number

class Solution:
    def letterCombinations(self, digits: str) -> List[str]:

        if not digits:
            return []

        DecimalToChar = {'2': ['a', 'b', 'c'],
                         '3':['d', 'e', 'f'],
                         '4':['g', 'h', 'i'],
                         '5':['j', 'k', 'l'],
                         '6':['m', 'n', 'o'],
                         '7':['p', 'q', 'r', 's'],
                         '8':['t', 'u', 'v'], 
                         '9':['w', 'x', 'y', 'z'],
                         '0':[' ']
                        }

        def combinations(strs1, strs2):
            combs = []
            for s1 in strs1:
                for s2 in strs2:
                    combs.append(s1 + s2)
            return combs


        strs = [DecimalToChar[s] for s in digits]        
        combs = strs[0]
        for s in strs[1:]:
            combs = combinations(combs, s)

        return combs
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