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rajanand ilangovan
rajanand ilangovan

Posted on • Originally published at blog.rajanand.org on

How to calculate total travel hours between city x and y and vice versa

Question

You are working for an airline company and you have received a dataset of Pilot's travel time between cities. You need to determine the reciprocal and find the total travel hours between cities. That means, the pilot's travel from city '1' to '2' and city '2' to '1' should be considered as one and then the total travel hours has to be calculated.

Write an SQL query to achieve the expected output.

04-reciprocal-input-data-output.png

Answer

Let us create the test data first.

--create test data
USE demo;

CREATE TABLE dbo.travel_detail (
    id int identity(1,1),
    from_city varchar(100),
    to_city varchar(100),
    travel_time_hours smallint
)
GO

INSERT INTO dbo.travel_detail values
    ('Oslo','Helsinki',125),
    ('Helsinki','Oslo',110),
    ('Stockholm','Oslo',132),
    ('Oslo','Stockholm',180),
    ('Copenhagen','Helsinki',148),
    ('Helsinki','Copenhagen',84),
    ('Stockholm','Copenhagen',116),
    ('Helsinki','Stockholm',124)
GO

SELECT * FROM dbo.travel_detail

--clean up
--USE demo;
--DROP TABLE dbo.travel_detail

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To achieve the desired result, you should swap the city names within the row based on some order. That means, you can sort the from_city and to_city names in a row in ascending or descending order and then keep the first city as city_1 and the other as city_2. To do this, you can use less than < or greater than > operator on from_city and to_city.

04-reciprocal-step-1.png

This way you will be able to aggregate the travel_time_hours by grouping city_1 and city_2.

--solution
USE demo;

select 
city_1,
city_2,
total_travel_hours = sum(travel_time_hours)
from (
    select 
    city_1 = case when from_city < to_city then from_city else to_city end,
    city_2 = case when from_city > to_city then from_city else to_city end,
    travel_time_hours
    from dbo.travel_detail
)x
group by city_1, city_2
order by city_1, city_2

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This is the solution I have come up with. If you have achieved the output in other way, let me know in comments.

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