Copy vs Reference in Javascript

Have you ever try to copy the value of an array and realized that new variable that you assigned is actually not a copy but a reference.
Sometimes we are intended to copy the value of an array or an object and apply the same method that we do to copy a normal string or a number like this:

let a = 1
let b = a;
console.log(a, b) // will return 1 1
b = 2
console.log(a,b) // will return 1 2

but if we try this it does not copy the value of array or object but instead create a reference and then whenever we try to change the value of second variable, the value of first one also changed like this:

const players = ['Wes', 'Rahul', 'Sarah'];
const team = players
console.log(players) // ['Wes', 'Rahul', 'Sarah']
console.log(team) // ['Wes', 'Rahul', 'Sarah']

team[2] = 'raj'
console.log(players) // ['Wes', 'Rahul', 'raj']
console.log(team) // ['Wes', 'Rahul', 'raj']

So in above code as we see, when we change the value of "team[2]", value of "players[2]" also changed. and same case is with objects, like this:

const person = {name:"Rahul", age:"21"}
const captain = person

captain.score = 50

console.log(person) // {name:"Rahul", age:"21", score:50}
console.log(captain)// {name:"Rahul", age:"21", score:50}

that is second variable become a reference of first one;

But than how to copy them?

Well here are some methods to do so:
for arrays:

1. using .slice()
2. using .concat()
3. using ES6 methods
4. using Array.from()

for objects:

1. using Object.assign()
2. using JSON.parse(JSON.stringify())

Implementation:

1).
For Arrays:

2.)
For Objects:
i) Using Object.assign():-
It will take 3 parameters:-

1. an empty object in order to copy
2. Object whom which we want copy
3. (optional) If we want any property to insert.

ii) using JSON.parse( JSON.stringify() ) :-

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