I tried timing your algorithm, with couple other implementations I wrote. One was recursive, one was iterative. Check this out.

# recursive def recursive_fibonacci(num, prev_num, sum=0): if num % 2 == 0: sum += num if num < 4000000: return recursive_fibonacci(num + prev_num, num, sum) return sum # iterative def iterative_fibonacci(num, second_num): sum = 0 while num < 4000000: if num % 2 == 0: sum += num temp = num num += second_num second_num = temp return sum # Other def fibonacci_sequence(n): numbers = [0, 1] while numbers[-1] < n: numbers.append(numbers[-1] + numbers[-2]) return numbers def sum_even_fibonacci_numbers(n): # O(N) Complexity sequence = fibonacci_sequence(n) sequence = [n for n in sequence if n % 2 == 0] return sum(sequence) import time start_time_recursive = time.time() print(recursive_fibonacci(1, 1)) print("--- Recursive %s seconds ---" % (time.time() - start_time_recursive)) start_time_iterative = time.time() print(iterative_fibonacci(1, 1)) print("--- Iterative %s seconds ---" % (time.time() - start_time_iterative)) start_time_other = time.time() print(sum_even_fibonacci_numbers(4000000)) print("--- Other %s seconds ---" % (time.time() - start_time_other))

The output was interesting!

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## re: Project Euler #2 - Even Fibonacci numbers VIEW POST

TOP OF THREAD FULL DISCUSSIONI tried timing your algorithm, with couple other implementations I wrote. One was recursive, one was iterative. Check this out.

The output was interesting!