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HHMathewChan
HHMathewChan

Posted on • Originally published at rebirthwithcode.tech

Python exercise 18:Sales Season

Question

  • A retailer is having a store-wide "buy 2, get 1 free" sale.
  • For legal reasons, they can't charge their customers $0 for an article
    • so a discount is applied to all products instead. - --
  • Create a function that takes in a list of prices for a customer's shopping cart
    • and returns the prices with the discount applied.
    • Round all prices to the cent.

Example

For example, if a customer gets three products a, b and c:

Product A Product B Product C
$15.99 $23.50 $23.50
  • She gets the cheapest one for free, so she ends up paying $15.99 + $23.50 = $39.49, but what her receipt says is:

  • Product A: $15.99 βˆ’ Special Discount = $12.57

  • Product B: $23.50 βˆ’ Special Discount = $18.47

  • Product C: $10.75 βˆ’ Special Discount = $8.45

  • Total: $39.49

My solution

  • algorithm
>>calculate the original price of all the products
  initialise a variable called original_total
  original_total = sum of the shopping cart
>>calculate the discount given in percentage
>>>determine how many product should be free
   free_product_number  = length of shopping cart // 3
>>>calculate the total price of the free product
>>>>find the lowest (numbers_of_free_product) price in the shopping cart
    initialise a free_product list
    while length of free_product list is not equal to free_product_number:
        for product in shopping cart:
            lowest_product = min(shopping cart)
            add the lowest_product to free_product list
            delete the lowest_product
   initialise a variable called discount_given
   discount_given = sum of the free_product list
>>>calculate the discount percentage
   discount percentage = 1-(discount_given / original_total)
>>return the list of all product price with discounted applied
  initialise a discounted_list
  for each product in the shopping cart:
      new_price = product * discount percentage
      then round the new_price to 2 decimal place
      store the new_price to the discounted list
  return the new_list     
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  • code
def discount(shopping_cart: list):  
    copy_of_shopping_cart = shopping_cart.copy()  
    # >>calculate the original price of all the products  
    original_total = sum(shopping_cart)  
    free_product_number = len(shopping_cart) // 3 
    # >>>calculate the total price of the free product  
    #    find the lowest (numbers_of_free_product) product in the shopping cart    free_product_list = list()  
    #  set up a loop for free_product_number times:  
    while len(free_product_list) < free_product_number:  
        free_product = min(copy_of_shopping_cart)  
        free_product_list.append(free_product)  
        # remove the lowest product in the shopping cart, so the next lowest product can be found  
        copy_of_shopping_cart.remove(free_product)  
    # calculate the total prise of the free item  
    discount_given = sum(free_product_list)  
    discount_percentage = 1 - (discount_given / original_total)  
    # >>return the list of all product price with discounted applied  
    discounted_list = list()  
    # applied discount to each product in the original list , round to 2 decimal place and add to discounted_list  
    for product in shopping_cart:  
        discounted_product = product * discount_percentage  
        discounted_list.append(round(discounted_product, 2))  
    return discounted_list
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Other solution

def discount(lst):
    free = len(lst) // 3
    # sorted the list in accedning order, and calculate the sum of the non_free item start from the index after the free item.
    pct = sum(sorted(lst)[free:]) / sum(lst)
    return [round(x*pct, 2) for x in lst]
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My reflection

  • I have learned a new way to solve the find lowest item in the list by using sorted()function and slicing method
  • seem like my code are very long compare to other, need to practice more the shorten code.

Credit

challenge find on edabit

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