Graph data structure with Java
class Graph {
class Edge {
int src, dest;
}
// Number of vertices and edges
int vertices, edges;
Edge[] edge;
Graph(int vertices, int edges) {
this.vertices = vertices;
this.edges = edges;
edge = new Edge[edges];
for (int i = 0; i < edges; i++) {
edge[i] = new Edge();
}
}
public static void main(String[] args) {
int numVertices = 5;
int numEdges = 7;
Graph g = new Graph(numVertices, numEdges);
g.edge[0].src = 1;
g.edge[0].dest = 2;
g.edge[1].src = 1;
g.edge[1].dest = 3;
g.edge[2].src = 1;
g.edge[2].dest = 4;
g.edge[3].src = 2;
g.edge[3].dest = 3;
g.edge[4].src = 2;
g.edge[4].dest = 4;
g.edge[5].src = 3;
g.edge[5].dest = 5;
g.edge[6].src = 4;
g.edge[6].dest = 5;
for (int i = 0; i < numEdges; i++) {
System.out.println(g.edge[i].src + " - " + g.edge[i].dest);
}
}
}
https://github.com/j143/java-graph-datastructure-example
Java Collection
s conversions
Java List
or ArrayList
to Array
ArrayList homekeys = new ArrayList<> ();
homekeys.add("A");
homekeys.add("S");
homekeys.add("D");
homekeys.add("F");
// Create new Array
String[] homekeysArray = new String[homekeys.size()];
homekeys.toArray(homekeysArray);
But, the other way around is simple
// import java.util.Arrays;
String[] array = {"A", "S", "D", "F"};
List languages = new ArrayList<> (Arrays.asList(array))
Based on the above learning I have solved https://leetcode.com/problems/rearrange-array-elements-by-sign/ but got Time Limit Exceeded.
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