Diagonal Difference Solution
Given a square matrix, calculate the absolute difference between the sums of its diagonals.
For example, the square matrix is shown below:
1 2 3
4 5 6
9 8 9
The left-to-right diagonal =1 + 5 + 9 = 15. The right to left diagonal = 3 + 5+ 9 = 17. Their absolute difference is |15–17| = 2.
Function description
Complete the diagonalDifference function in the editor below. It must return an integer representing the absolute diagonal difference.
Difference takes the following parameter:
arr: an array of integers.
Input Format
The first line contains a single integer, n , the number of rows and columns in the matrix arr.
Each of the next n lines describes a row, arr[i], and consists of n space-separated integers arr[i][j].
Constraints
. — 100 ≤ arr[i][j] ≤ 100
Output Format
Print the absolute difference between the sums of the matrix’s two diagonals as a single integer.
Sample Input
11 2 4
4 5 6
10 8 -12
Sample Output
15
Explanation
The primary diagonal is:
11
5
-12
Sum across the primary diagonal: 11 + 5–12 = 4
The secondary diagonal is:
4
5
10
Sum across the secondary diagonal: 4 + 5 + 10 = 19
Difference: |4 –19| = 15
Note: |x| is the absolute value of x
Solution (Base on how i solved it)
$first = 0;
$second = 0;
$n = sizeof($arr);
for ($i = 0; $i < $n; $i++){
for ($j = 0; $j < $n; $j++){
if ($i === $j){
$first += $arr[$i][$j];
}
if ($i + $j === $n - 1){
$second += $arr[$i][$j];
}
}
}
return abs($first - $second);
}
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