Statement :-
Given a list of N students, every student is marked for M subjects. Each student is denoted by an index value. Their teacher Ms. Margaret must ignore the marks of any 1 subject for every student. For this she decides to ignore the subject which has the lowest class average.
Your task is to help her find that subject, calculate the total marks of each student in all the other subjects and then finally return the array of the total marks scored by each student.
Input Specification:
input1:
An integer value N denoting number of students
input2:
An integer value M denoting number of subjects
input3:
A 2-D integer array of size N'M containing the marks of all students in each subject.
Output Specification:
Return an integer array of size N containing the total marks of each student afte deducting the score for that one subject.
Example 1:
INPUT
3 5
75 76 65 87 87
78 76 68 56 89
67 87 78 77 65
OUTPUT
325 299 296
Example 2:
INPUT
3 3
50 30 70
30 70 99
99 20 30
OUTPUT
120 129 129
Explanation:
Out of these subjects, the students average was lowest in subject 2
i.e 30+70+20= 120/3=40
So the teacher will ignore marks of this subject and will consider the title other two subjects for each of the three students i.e. 120 129 129 respectively
Hence (120 129 129) is returned as the final output.
Solution:-
import java.util.*;
public class MyClass {
public static void main(String args[]) {
Scanner sc = new Scanner(System.in);
int row = sc.nextInt();
int col = sc.nextInt();
int avg[]= new int[row];
int ans[] = new int[row];
int arr[][]= new int[row][col];
int res[]= new int[row];
for(int i = 0; i <row; i++) {
for(int j=0;j<col;j++) {
arr[i][j]= sc.nextInt();
}
}
/*//verifying i/p
for(int i = 0; i <row; i++) {
for(int j=0;j<col;j++) {
System.out.print(arr[i][j]+" ");
}
System.out.println("");
}*/
for(int i = 0; i <row; i++) { //calculating and storing average of each column
for(int j=0;j<row;j++) {
ans[i] += arr[j][i];
}
avg[i] = ans[i]/row;
}
int min = avg[0];
int eleminate_Index =0;
for(int i = 1; i < row; i++) { // minimum average calculated and ..
if(avg[i]<min) {
min = avg[i];
eleminate_Index = i; //..index of it stored.
}
}
/*
System.out.println(min);
System.out.println(p);
*/
for(int i = 0 ; i<row; i++) {
for(int j=0; j<col; j++){
if(eleminate_Index!=j) {//calculating sum of remaining subjects
res[i]+=arr[i][j];
}
}
}
for(int j=0; j<row; j++){
System.out.print(res[j]+" ");
}
sc.close();
}
}
Top comments (6)
Need same solution in swift 5
import Foundation
let sc = Scanner.standardInput
let row = sc.nextInt()!
let col = sc.nextInt()!
var avg = Int
var ans = Int
var arr = [Int]
var res = Int
for i in 0..<row {
for j in 0..<col {
arr[i][j] = sc.nextInt()!
}
}
///verifying i/p
for i in 0..<row {
for j in 0..<col {
print(arr[i][j], terminator: " ")
}
print("")
}/
for i in 0..<row { //calculating and storing average of each column
for j in 0..<row {
ans[i] += arr[j][i]
}
avg[i] = ans[i]/row
}
var min = avg[0]
var eleminate_Index = 0
for i in 1..<row { // minimum average calculated and ..
if avg[i] < min {
min = avg[i]
eleminate_Index = i //..index of it stored.
}
}
/*
print(min)
print(p)
*/
for i in 0..<row {
for j in 0..<col {
if eleminate_Index != j {//calculating sum of remaining subjects
res[i] += arr[i][j]
}
}
}
for j in 0..<row {
print(res[j], terminator: " ")
}
sc.close()
Same problem statement for Nagarro.
Need same solution in C#
using System;
using System.Linq;
class Program {
static void Main() {
int N = 3; // number of students
int M = 4; // number of subjects
}
C#
using System;
using System.Linq;
class Program {
static void Main() {
int N = 3; // number of students
int M = 4; // number of subjects
}