Use the getClass().getClassLoader().getResourceAsStream() to get an InputStream for the wanted resource. In the following snippet we access the bookmark-example.xml file resource, which is placed directly in the src/test/resources folder:
@Test
void shouldUnmarshallXmlToJava() throws JAXBException {
JAXBContext jaxbContext = JAXBContext.newInstance("dev.codepal.bookmark");
final var jaxbUnmarshaller = jaxbContext.createUnmarshaller();
InputStream inStream = getClass().getClassLoader().getResourceAsStream(
"bookmark-example.xml");
JAXBElement<Bookmark> o = (JAXBElement<Bookmark>)jaxbUnmarshaller.unmarshal(inStream);
Bookmark bookmark = o.getValue();
assertThat(bookmark.getTitle(), equalTo("CodepediaOrg"));
}
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