DEV Community

Discussion on: Daily Challenge #224 - Password Validator

View post
Collapse
 
vidit1999 profile image
Vidit Sarkar •

Python solution

passwordValidator = lambda password : "VALID" if((3 < len(password) < 20) and password.isalnum() and any(map(str.isdigit, password)) and any(map(str.isalpha, password))) else "INVALID"

Here is the detailed version of above,

def passwordValidator(password : str) -> str:
    if(3 < len(password) < 20):
        if(password.isalnum()):
            if(any(map(str.isdigit, password)) and any(map(str.isalpha, password))):
                return "VALID"
    return "INVALID"

Output,

print(passwordValidator('Username123!')) # output -> INVALID
print(passwordValidator('123')) # output -> INVALID
print(passwordValidator('Username123')) # output -> VALID
print(passwordValidator('Username')) # output -> INVALID
print(passwordValidator('IsThisPasswordTooLong')) # output -> INVALID
print(passwordValidator('DEVCommunity')) # output -> INVALID
Collapse
 
mburszley profile image
Maximilian Burszley •

A little more readable example that is explicit about the lazy evaluation (chaining and)

def validatePassword(password: str) -> str:
    if (3 < len(password) < 20
            and password.isalnum()
            and any(map(str.isdigit, password))
            and any(map(str.isalpha, password))):
        return 'VALID'
    return 'INVALID'

assert validatePassword('Username123!') == 'INVALID'
assert validatePassword('123') == 'INVALID'
assert validatePassword('Username123') == 'VALID'

assert validatePassword('Username') == 'INVALID'
assert validatePassword('IsThisPasswordTooLong') == 'INVALID'
assert validatePassword('DEVCommunity') == 'INVALID'