Discussion on: What’s your favorite JS interview question?

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Replies for: What will be output of (() => console.log(this)).bind("done")() var fx = (() => console.log(this)); fx.call("done"); Enter fullsc...

Tiago Romero Garcia • Dec 27 '18 • Edited

Great question! I believe this is because arrow functions can't be bound and also don't have arguments, for that we need to use regular function definitions:

(function() { console.log(this) }).bind("done")();

var fx = (function() { console.log(this) });
fx.call("done");

(function() { console.log(arguments) })("a");

Jonas Winzen • Dec 27 '18

You can't bind anything to an arrow functions this. But you can bind arguments to them. ie:

((arg) => console.log(arg)).bind(null, "done")()

would work.

Tiago Romero Garcia • Dec 27 '18

Oh nice! Thanks for explaining that.