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re: Daily Challenge #3 - Vowel Counter VIEW POST

FULL DISCUSSION
 

Thinking the string as a Set with O(1) for look up operations: solution is O(n), where n = len(str)

def count_vowels(str):
    vowels = "aeiouAEIOU"
    count = 0
    for c in str:
        if c in vowels:
            count += 1
    return count;

JS lambda way

conat vowels = new Set("aeiouAEIOU");
const counVowels = input => [...input].reduce((total, current) => (total += vowels.has(current)), 0);
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