Trying to develop an android application using python and kivymd..
can anyone help me solve the error in the following code file
code --
from kivy.animation import Animation
from kivy.clock import Clock
from kivymd.app import MDApp
from kivy.uix.image import Image
from kivymd.uix.screenmanager import ScreenManager
from kivy.uix.screenmanager import Screen
... (Other imports and classes)
class SplashScreen(Screen):
def on_enter(self):
self.animate_logo()
Clock.schedule_once(self.transition_to_main_screen, 3) # Adjust transition time as needed
def animate_logo(self):
logo_image = self.logo_image
if logo_image:
anim = Animation(size_hint_x=1.2, duration=0.5)
anim.bind(on_complete=self.animate_logo_back)
anim.start(logo_image)
def animate_logo_back(self, *args):
logo_image = self.logo_image
if logo_image:
anim = Animation(size_hint_x=1, duration=0.5)
anim.start(logo_image)
def transition_to_main_screen(self, dt):
self.manager.current = 'main_screen' # Replace 'main_screen' with your main screen name
... (Other imports and classes)
class MainScreen(Screen):
# ... (Other screen logic)
def login(self):
# Implement your login logic here
username = self.ids.username_field.text
password = self.ids.password_field.text
# ... (Check credentials, navigate to appropriate screen)
def show_signup_screen(self):
self.manager.current = 'signup_screen' # Replace with your signup screen name
... (Rest of your MainApp and other classes)
class MainApp(MDApp):
# ... (Other app logic)
def build(self):
sm = ScreenManager()
sm.add_widget(SplashScreen(name='splash_screen'))
sm.add_widget(MainScreen(name='main_screen')) # Add your main screen
sm.current = 'splash_screen'
return sm
if name == 'main':
MainApp().run() # Ensure app runs only when executed as a script
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