My approach is to take advantage of string replace 🤣️
const n = 15; for (let i = 1; i <= n; i++) { const fizz = ['Fizz'][i % 3]; const buzz = ['Buzz'][i % 5]; const value = `${fizz}${buzz}` .replace('undefinedundefined', i) .replace('undefined', ''); console.log(value); }
Smart!
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My approach is to take advantage of string replace 🤣️
Smart!