🤔 Situation
I have a STI model named Media which has two chirdren models which are Photo and Video. And I've wanted to not change the view logic by each class.
Example
<% @album.media.each do |medium| %>
<div>
<%= file_content(medium) %>
</div>
<% end %>
😅 But I didn't want to write like this.
If I ask object about class and then switch the logic, it's not OOP anymore. I have to write again when I add a new class like 'text', 'sound'.
module MediaHelper
def file_content(medium)
return nil unless medium.file.attached?
if medium.class == Photo
return photo_content(medium)
else
return video_content(medium)
end
end
end
👍 How have I solved it?
I wrote the helper like this.
module MediaHelper
def file_content(medium)
return nil unless medium.file.attached?
send("#{medium.class.name.underscore}_content", medium)
end
end
module PhotosHelper
def photo_content(medium)
# do something
end
end
module VideosHelper
def video_content(medium)
# do something
end
end
🦄 But, I believe there is a better way.
I don't know it works. But I hope I will change my code like this.
1. remove the parent helper
# module MediaHelper
# def file_content(medium)
# return nil unless medium.file.attached?
# send("#{medium.class.name.underscore}_content", medium)
# end
# end
2. align the children's helper names.
module PhotosHelper
def file_content(medium)
# do something
end
end
module VideosHelper
def file_content(medium)
# do something
end
end
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