Found a solution:
re.findall(r'[R]+\d+\.?\d*', 'R31.99Save\xa05.00') Returns: ['R31.99']
If that first character is only ever going to be a single 'R', you can replace the [R]+ in the regex with just R:
'R'
[R]+
R
>>> re.findall(r'R\d+\.?\d*', 'R31.99Save\xa05.00') ['R31.99']
Any character in the pattern that doesn't have some special regex meaning will match the character itself.
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Found a solution:
If that first character is only ever going to be a single
'R'
, you can replace the[R]+
in the regex with justR
:Any character in the pattern that doesn't have some special regex meaning will match the character itself.