This blog post will speak about Week Two Part 1, which contains the lab 2
You can view Lab 1 using the cdot wiki here but in essence I had to draw 4 lines around a square in different colours.
Sounds easy right? Well, it's surprisingly difficult when you are working with 6502 Assembly code.
Below is my entire code for the program:
lda #$00 ; load A with 00
sta $40 ; set lowbit to 00
lda #$02 ; load A with 02
sta $41 ; set highbit to 02 (0200)
lda #$05 ; load a with color green
ldy #$00 ; set y index to 0
top: sta ($40),y ; store A inside memory location $40+y highbit is 02, lowbit is 00 so 0200+y
iny ; increment y
CPY #$20 ; compare y to hash value 20 (dec 32)
bne top ; if y does not equal #$20 go back to top
lda #$05 ; load accumulator with final page (0500)
sta $41 ; store a inside highbit
lda #$06 ; load blue color into A
ldy #$e0 ; load final line in Y (05e0)
bottom: sta ($40),y ; store A inside memory location $40+y highbit is 05, lowbit is e0 so 05e0+y
iny ; increment y
cpy #$ff ; compare y to hash value ff (end of line 05ff)
bne bottom ; get out of loop once you go to next page
ldy #$00 ; reset Y to 00 (follow commands are to reset pixel to first line first pixel)
lda #$00 ; load A to 00
sta $40 ; store A inside lowbit
lda #$02 ; load A with 02
sta $41 ; store A inside highbit
left_to_right:
lda #$07 ; load A with colour yellow
sta ($40),y ; store A inside memory location $40+y highbit is 02, lowbit is 00 so 0200+y (will change after first loop = 0200)
tya ; transfer y to a
clc ; clear counter bit for next line since we are adding
adc #$1f ; this addition skips to the other side of the bitmap
tay ; transfer a to y
lda #$04 ; load A with colour purple
sta ($40),y ; store A inside memory location $40+y highbit is 02, lowbit is 00 so 0200+y (will change after first loop = 021f)
iny ; increment y
bne left_to_right ; restart loop until end of page
inc $41 ; increment highbit to next page (first loop goes from 02 to 03)
ldx $41 ; load x with current page
cpx #$06 ; compare page to 06 (05ff is final pixel of bitmap so if it equals highbit equals 06 we are outside of bitmap)
bne left_to_right ; restart loop if current page (highbit) does not equal 6
Here is what it outputs: 
You can actually run the code yourself here
As you can see, it doesn't even look that great. Just 4 flat plain colours around the border of a square. But it was actually fun & interesting while I was working on it.
Something that I had trouble understanding was why we used memory location 40 when storing the accumulator when memory location 41 was where the actual page number was stored (40 just always contained 00).
Well Chris came to my rescue and explained to me that 6502 is something called 'little endian' which basically means that the memory locations are split in two, the lowbyte and the highbyte.
Take a look at this line and it might help you understand as well:
sta ($40),y ; store A inside memory location $40+y highbit is 02, lowbit is 00 so 0200+y
Basically we use the lowbyte to access the entire point in memory (40 = 0200).
Once I understood this concept the rest was fairly straight forward!
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