You're right, it's been a while since I've had to do time complexity, I'll update it.
I had to double-check myself that n log(n) is higher order than n :)
n log(n)
n
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You're right, it's been a while since I've had to do time complexity, I'll update it.
I had to double-check myself that
n log(n)is higher order thann:)