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Leetcode Problem Link: 169. Majority Element
Brute Force Solution : Time O(NlogN) & Auxiliary Space O(1)
class Solution {
public:
int majorityElement(vector<int>& nums) {
// Brute Force Solution
sort(nums.begin(),nums.end());
return nums[nums.size()/2];
}
};
Better Solution : Time O(N) & Auxiliary Space O(N)
class Solution {
public:
int majorityElement(vector<int>& nums) {
// Better Solution
map<int,int> m;
int len=nums.size(), pos;
for(int i=0;i<len;i++){
m[nums[i]]++;
if(m[nums[i]]>(len/2))
pos=i;
}
return nums[pos];
}
};
Optimal Solution : Time O(N) & Auxiliary Space O(1)
class Solution {
public:
int majorityElement(vector<int>& nums) {
// Optimal Solution
// Boyer–Moore Majority Voting Algorithm
int len=nums.size(), maj=nums[0], count=1;
for(auto i=1;i<len;i++){
if(nums[i]==maj)
count++;
else
count--;
if(count==0){
maj=nums[i];
count=1;
}
}
return maj;
}
};
All suggestions are welcome. Please upvote if you like it. Thank you.
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