This method uses a for loop to go through each character. It converts each character to lower case for a case insensitive comparison with "x" and "o" and increments the respective counters. The return line checks for count equality to return a boolean.
The time complexity in big O notation is O(n) or linear, where n is the size of input string s, and the space complexity is O(1) or constant since it just uses two variables to keep track of counts.
A little Python here.
This method uses a for loop to go through each character. It converts each character to lower case for a case insensitive comparison with "x" and "o" and increments the respective counters. The return line checks for count equality to return a boolean.
The time complexity in big O notation is
O(n)
or linear, wheren
is the size of input strings
, and the space complexity isO(1)
or constant since it just uses two variables to keep track of counts.Is there a reason why you prefer a for loop over a single call to lower on the str, and then returning lowered.count('x') == lowered.count('o') ?