Selection sort is simple and easy to implement. But it is also very inefficient in terms of time complexity.

## Time Complexity

- Best:
**Ω(n^2)** - Average:
**Ω(n^2)** - Worst:
**Ω(n^2)**

In selection sort, we loop through the array by selecting the smallest value and then swapping it to the left side of the array till it is sorted in ascending order.

## Code

```
const selectionSort = (arr: number[]): number[] => {
const len: number = arr.length;
let minInd: number = -1;
for (let i = 0; i < (len - 1); i++) {
minInd = i
for (let j = (i + 1); j < len; j++) {
if (arr[j] < arr[minInd]) {
minInd = j
}
}
if (minInd !== i) {
[arr[i], arr[minInd]] = [arr[minInd], arr[i]];
}
}
return arr;
}
const result = selectionSort([64, 25, 12, 22, 11]);
```

## Output

```
Output: [11, 12, 22, 25, 64]
```

Here how the code is working

- The function takes the unsorted array [64, 25, 12, 22, 11].
- Iteration 1: [
__11__, 25, 12, 22,__64__] → i = 0, minInd = 4 and min value is 11. - Iteration 2: [11,
__12__,__25__, 22, 64] → i = 1, minInd = 2 and min value is 12. - Iteration 3: [11, 12,
__22__,__25__, 64] → i = 2, minInd = 3 and min value is 22. - Iteration 4: [11, 12, 22,
__25__, 64] → i = 3, minInd = 3 and min value is 25. - For iteration 4 it won't swap the value as the minInd and i are the same so there are no unnecessary swap.

That’s all for the selection sort, thanks for reading!

## Top comments (1)

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