The replace all trick with regexp will work only if string to search doesn't contain regexp metacharacters like ., ^, etc. You'll have to escape them first. developer.mozilla.org/en-US/docs/W... provides an escape function.
functionescapeRegExp(string){returnstring.replace(/[.*+?^${}()|[\]\\]/g,'\\$&');}'abc a;c a.c apc a.c'.replace(/a.c/g,'X')// gives "X X X X X"'abc a;c a.c apc a.c'.replace(newRegExp(escapeRegExp('a.c'),'g'),'X')// gives "abc a;c X apc X"
The replace all trick with regexp will work only if string to search doesn't contain regexp metacharacters like
.,^, etc. You'll have to escape them first. developer.mozilla.org/en-US/docs/W... provides an escape function.String.prototype.replaceAllis proposed to avoid such issues: github.com/tc39/proposal-string-re...Interesting.
Thank you for sharing that with us.