Prime Numbers:
Numbers which are divisible by 1 and itself are called as prime numbers.(Eg-->3,5,7)
1) Find prime number or not:
no = int(input("Enter no. "))
div = 2
while div<no:
if no%div == 0:
print("Not Prime")
break
div+=1
else:
print("Prime")
Output:
1)Enter no. 5
Prime
2)Enter no. 6
Not Prime
2) Reversing the input number and find whether that reversed number is prime number or not:
def reverse_a_no(no):
reverse = 0
while no>0:
rem = no%10
reverse = (reverse*10) + rem
no//=10
return reverse
no = int(input("Enter no. "))
reversed_no = reverse_a_no(no)
print(reversed_no)
def find_prime(no):
div = 2
while div<no:
if no%div == 0:
return False
break
div+=1
else:
return True
result1 = find_prime(no)
result2 = find_prime(reversed_no)
if result1 == result2:
print("EMIRP number")
else:
print("not EMIRP number")
Output:
1)Enter no. 15
51
EMIRP number
2)Enter no. 14
41
not EMIRP number
Perfect Number
Perfect number means sum of its divisible numbers will be equal that number.(eg-->6 is divisible by 1,2,3 and 1+2+3=6)
def find_perfect(no):
total = 0
div = 1
while div<no:
if no%div==0:
total = total + div
div+=1
else:
if total == no:
return True
else:
return False
no = int(input("Enter no. "))
result = find_perfect(no)
if result == True:
print("Perfect Number")
else:
print("Not Perfect")
Output:
Enter no. 6
Perfect Number
Square root:
Find square of an input number and sum of digits of that square root number.
def square(no):
return no**2
no=int(input("Enter the number:"))
result=square(no)
def sum_of_digits(num):
sum=0
while num>0:
sum=sum+num%10
num=num//10
return sum
if result<10:
print(result)
else:
final_result=sum_of_digits(result)
if final_result<10:
print(final_result)
else:
final_result=sum_of_digits(final_result)
print("sum_of_digits:",final_result)
Output:
Enter the number:4
7
In above example given input number is 4,
-->square root of 4 is 4x4=16
-->sum of digits of that square number 1+6=7.
Task -1 **
**Automorphic Number
Check if a number’s square ends with the same number.
Example: 5 → Automorphic (5²=25), 6 → Automorphic (6²=36), 7 → Not Automorphic.
def square(no):
return no ** 2
def find_automorphic(no):
while result > 0:
rem = result % 10
if rem == no:
print("Automorphic number")
break
else:
print("Not Automorphic number")
break
no = int(input("Enter the number: "))
result = square(no)
print(result)
find_automorphic(no)
Output:
1)Enter the number:5
25
Automorphic number
2)Enter the number:4
16
Not Automorphic number
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