JS Challenge: Check if an array has all its values sorted in the ascending order

#javascript #javascripttips #jschallenge #oneliners

We can use every() method of array to check if condition is true for every element of the array. So our solution using every() method goes like this:

arr1 = [1, 2, 3, 4, 6, 5];
arr2 = [1, 2, 3, 4, 5, 6];

arr1.every((element, index, array) => 
  index === 0 || element >= array[index - 1]
)

arr2.every((element, index, array) => 
  index === 0 || element >= array[index - 1]
)