Thanks for the great article. However in my environment, if I run the example, it will print the escape code literally. e.g.
$ echo -e "\e[32mRed text\e[0m" \e[32mRed text\e[0m
For me the solution is to use printf, e.g.
printf
echo -e $(printf "\e[32mRed text\e[0m")`
This helped me as well in macOS. Thank you!
Try using -ne rather than -e.
-ne
-e
Try $ echo -e "\033[32mRed text\e[0m" \e[32mRed text\033[0m. i.e. \033 instead \e.
$ echo -e "\033[32mRed text\e[0m" \e[32mRed text\033[0m
\033
\e
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Thanks for the great article. However in my environment, if I run the example, it will print the escape code literally. e.g.
For me the solution is to use
printf, e.g.This helped me as well in macOS. Thank you!
Try using
-nerather than-e.Try
$ echo -e "\033[32mRed text\e[0m". i.e.\e[32mRed text\033[0m
\033instead\e.