Jagroop Singh

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Must do pattern questions :Part-2 [ Javascript]

After learning how to build some basic pattern in Javascript. I come with with part-2 with more complex patterns.

If you directly come to this second blog , then please checkout my first blog of : Must do Pattern Questions : Part 1 [Javascript]

So today In this part I am sharing 5 patterns where we have to think a bit more than previous patterns that is available in Part-1 of the blog and we will solve this in JavaScript.

``````// 1
// 2 3
// 4 5 6
// 7 8 9 10
// 11 12 13 14 15

const pattern = (n) => {
let patternCapturer = "";
let counter = 0;
for (let i = 0; i < n; i++) {
for (let j = 0; j <= i; j++) {
counter++;
patternCapturer += `\${counter} `;
}
patternCapturer += "\n";
}
console.log(patternCapturer);
};

pattern(5);
``````
``````// A
// AB
// ABC
// ABCD
// ABCDE

const alphabetPattern = (n) => {
let patternCapturer = "";
for (let i = 1; i <= n; i++) {
let alphabetIndex = 65;
for (let j = 1; j <= i; j++) {
patternCapturer += `\${String.fromCharCode(alphabetIndex)}`;
alphabetIndex++;
}
patternCapturer += "\n";
}
console.log(patternCapturer);
};
alphabetPattern(5);
``````
``````// ABCDE
// ABCD
// ABC
// AB
// A

const alphabetPatternReverse = (n) => {
let patternCapturer = "";
for (let i = 1; i <= n; i++) {
let alphabetIndex = 65;
for (let j = n; j >= i; j--) {
patternCapturer += `\${String.fromCharCode(alphabetIndex)}`;
alphabetIndex++;
}
patternCapturer += "\n";
}
console.log(patternCapturer);
};
alphabetPatternReverse(5);
``````
``````// A
// BB
// CCC
// DDDD
// EEEEE

const alphabetPatternIdentical = (n) => {
let patternCapturer = "";
let alphabetIndex = 65;
for (let i = 1; i <= n; i++) {
for (let j = 1; j <= i; j++) {
patternCapturer += `\${String.fromCharCode(alphabetIndex)}`;
}
alphabetIndex++;
patternCapturer += "\n";
}
console.log(patternCapturer);
};
alphabetPatternIdentical(5);

``````
``````// *****
// *   *
// *   *
// *   *
// *****

const hollowSquarePattern = (n) => {
let patternCapturer = "";
for (let i = 1; i <= n; i++) {
if (i == 1 || i == n) {
for (let j = 1; j <= n; j++) {
patternCapturer += "* ";
}
} else {
for (let j = 1; j <= n; j++) {
if (j == 1 || j == n) {
patternCapturer += "* ";
} else {
patternCapturer += " ";
}
}
}
patternCapturer += "\n";
}

console.log(patternCapturer);
};

hollowSquarePattern(5);

``````

Top comments (4)

Web

I am waiting for the part 2 of this and it's finally there.

Jagroop Singh

I'm happy that my content is useful for you !!

Sergey Leschev

You have done a great job in exploring some complex patterns using Javascript.

Jagroop Singh

Thanks you @sergeyleschev !!