Check if a string has the same amount of 'x' and 'o'. The method must return a Boolean value and must not be case-sensitive. The string can contain any char.
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Check if a string has the same amount of 'x' and 'o'. The method must return a Boolean value and must not be case-sensitive. The string can contain any char.
For further actions, you may consider blocking this person and/or reporting abuse
Alin Climente -
zhuyue -
Probir Sarkar -
Sidali Assoul -
Top comments (12)
Python solution -
Thank you @Pierre for pointing out the error.
Hey @ganeshtata !
I think you missed an uppercase in your
elif
:)instead of
To dig a little deeper, I suggest you to see some very useful string methods in Python !
Thank you for that! I had not noticed it. Yes, there are some awesome string methods in Python, but I didn't use any of them here because I wanted to finish the count(s) in one pass of the string. Doing a
.lower()
and then counting might involve two passes of the same string.I suggested it to reduce your conditions, lowering the string before checking would have allowed you to only check for
o
andx
for example. This way you would have one pass on the string and a more concise condition :)Do you mean lowering the string before the loop or lowering the character in the loop before checking whether it is an 'x' or 'o'?
.lower()
on the character.Oh right, nevermind !
In Haskell, with what I thought was kind of a neat method:
As a javascript one-liner:
A simple solution with Rust.
Python to the rescue !
output
Time for a Go kata you say?
play.golang.org/p/n8q9BYrsW4a
Rust Solution.
Ruby Solution!