It may have, performance implications in some languages. Think of these operators as functions (functors, I believe) as for ++x you'd something like:
public int ++operator (int &x) {
x = x + 1;
return x;
}
And for x++ you have something like
public int operator++ (int &x) {
int tmp = x;
x = x + 1;
return tmp;
}
As you can see, from the second example above, there is one more instruction needed to store the previous value of x and then return it.
But I don't think there is a major impact unless you use it extensively, also todays compilers may or may not predict and optimize the end result.
PS: the examples above only work in languages that have the concept of functors (function operators) like C++ does.
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It may have, performance implications in some languages. Think of these operators as functions (functors, I believe) as for ++x you'd something like:
public int ++operator (int &x) {
x = x + 1;
return x;
}
And for x++ you have something like
public int operator++ (int &x) {
int tmp = x;
x = x + 1;
return tmp;
}
As you can see, from the second example above, there is one more instruction needed to store the previous value of x and then return it.
But I don't think there is a major impact unless you use it extensively, also todays compilers may or may not predict and optimize the end result.
PS: the examples above only work in languages that have the concept of functors (function operators) like C++ does.