x = (x++ , x = addFive(x), x *= 2, x -= 5, x += 10);
function addFive(num) {
return num + 5;
}
If you log the value of x it would be 27. First, we increment the value of x it would be 6, then we invoke the function incrementBy5(6) and pass the 6 as a parameterβ
βlet x = 5;
x = (x++ , x = addFive(x), x *= 2, x -= 5, x += 10);
function addFive(num) {
return num + 5;
}
If you log the value of x it would be 27. First, we increment the value of x it would be 6, then we invoke the function incrementBy5(6) and pass the 6 as a parameterβ
Do you mean addFive(6)?
Iβm new to js, so Iβm probably wrong.
Thanks for telling me this little problem π
Thanks for writing the article. Iβm enjoying it.
Also,
reduce.apply(obj1, [1, 2, 3, 4, 5]); // returns 15
reduce.apply(obj2, 1, 2, 3, 4, 5); // returns 15
Did you mean reduce.call obj2, 1, 2, 3, 4, 5); ?
Thanks again π