herp derp, realized it myself just now, ∀x(P(x))->Q ≠ ∀x(P(x)->Q).
∀x(P(x))->Q ≠ ∀x(P(x)->Q)
So this would require an an ad-hoc polymorphic function as argument, yes?
Correct 👍
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herp derp, realized it myself just now,
∀x(P(x))->Q ≠ ∀x(P(x)->Q).So this would require an an ad-hoc polymorphic function as argument, yes?
Correct 👍