The question is to return true if the number is perfect square otherwise false.
A perfect square is an integer that is the square of an integer.
Javascript provides numerous ways to write a code for this. I will let you know that this is what I did:
const isSquare = (n) => {
return (Math.sqrt(n) === Math.ceil(Math.sqrt(n)));
}
Below is the solution that impressed me, because it is simple Math my brain couldn't get hold of first:
const isSquare = function(n){
return Math.sqrt(n) % 1 === 0;
}
And it is clever and also follows the best practices!
Checking the datatype would also work using isInteger. But you never know when it would get obsolete! Languages change but the Math around remains the same! Choose better!
Oldest comments (4)
I used Number.isInteger detect if the square is integer github.com/itsjzt/euler-project/bl...
That is very much correct. It shows your knowledge in the language is really good. Also, it is always better to know the underlying operations. :)
Stack overflow
The solution doesn't matter, when you get it, you need to understand and ask why ;)