The given algorithm is simple, but runs in quadratic time. You can use Sets to make the includes check faster.
Set
includes
const inLeft = new Set(left); const inRight = new Set(right); return left.filter(x => !inRight.has(x)).concat(right.filter(x => !inLeft has(x));
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The given algorithm is simple, but runs in quadratic time. You can use
Set
s to make theincludes
check faster.